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#1 2020-02-11 14:39:36

rs4
Member
Registered: 2009-11-15
Posts: 2

Siemens Sinumerik 840D G02 G03 circular interpolation error

Good morning

Siemens 840D the vericut I can't read the following interpolation "I and J" cyclic G02 G03, what are the parameters to be set and in which file ??

Signaling: Incorrect circular interpolation. r1 = 0.999914, r2 = 0.999831

block example:G02 X56.574 Y-236.346 I = AC (56.32547) J = AC (-235.37755)

thank you

Last edited by rs4 (2020-02-11 15:22:14)

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#2 2020-02-13 13:33:56

tstretton
Moderator
From: Crewe, England
Registered: 2007-02-20
Posts: 86
Website

Re: Siemens Sinumerik 840D G02 G03 circular interpolation error

Go to Control Settings > General > increase the Calculation Tolerance slightly


Tony

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#3 2020-02-13 14:05:33

rs4
Member
Registered: 2009-11-15
Posts: 2

Re: Siemens Sinumerik 840D G02 G03 circular interpolation error

Thanks Tony

Now it works you were very kind, I set 0.0254mm as the value.

Last edited by rs4 (2020-02-13 14:05:52)

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#4 2020-02-13 14:50:06

tstretton
Moderator
From: Crewe, England
Registered: 2007-02-20
Posts: 86
Website

Re: Siemens Sinumerik 840D G02 G03 circular interpolation error

0.0254 is fine.


Tony

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