VERICUT Users' Forum
Due to relentless spammers, we are no longer automatically accepting new forum registrations. If you wish to register for this forum, please send an e-mail to: info@cgtech.com
You are not logged in.
- Topics: Active | Unanswered
#1 2020-02-11 14:39:36
- rs4
- Member
- Registered: 2009-11-15
- Posts: 2
Siemens Sinumerik 840D G02 G03 circular interpolation error
Good morning
Siemens 840D the vericut I can't read the following interpolation "I and J" cyclic G02 G03, what are the parameters to be set and in which file ??
Signaling: Incorrect circular interpolation. r1 = 0.999914, r2 = 0.999831
block example:G02 X56.574 Y-236.346 I = AC (56.32547) J = AC (-235.37755)
thank you
Last edited by rs4 (2020-02-11 15:22:14)
Offline
#2 2020-02-13 13:33:56
- Tony
- Moderator
- From: Crewe, England
- Registered: 2007-02-20
- Posts: 181
- Website
Re: Siemens Sinumerik 840D G02 G03 circular interpolation error
Go to Control Settings > General > increase the Calculation Tolerance slightly
Tony
Offline
#3 2020-02-13 14:05:33
- rs4
- Member
- Registered: 2009-11-15
- Posts: 2
Re: Siemens Sinumerik 840D G02 G03 circular interpolation error
Thanks Tony
Now it works you were very kind, I set 0.0254mm as the value.
Last edited by rs4 (2020-02-13 14:05:52)
Offline
#4 2020-02-13 14:50:06
- Tony
- Moderator
- From: Crewe, England
- Registered: 2007-02-20
- Posts: 181
- Website
Re: Siemens Sinumerik 840D G02 G03 circular interpolation error
0.0254 is fine.
Tony
Offline